functions - syntax error, unexpected '$id' (T_VARIABLE) - where is the issue though?

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This function below throws the following error: "syntax error, unexpected '$id' (T_VARIABLE)"

This function and question is related to this post.

function so328323_prefix_title( $title, $id = null ) {

    if ( get_post_type $id ) == 'tools-in-2019' {
        $title = "123 " . $title;
    }

    return $title;
}
add_filter( 'the_title', 'so328323_prefix_title', 10, 2 );

Closed. This question is off-topic. It is not currently accepting answers.

---

Questions that are too localized (such as syntax errors, code with restricted access, hacked sites, hosting or support issues) are not in scope. See how do I ask a good question?

Closed 6 years ago.

Improve this question

This function below throws the following error: "syntax error, unexpected '$id' (T_VARIABLE)"

This function and question is related to this post.

function so328323_prefix_title( $title, $id = null ) {

    if ( get_post_type $id ) == 'tools-in-2019' {
        $title = "123 " . $title;
    }

    return $title;
}
add_filter( 'the_title', 'so328323_prefix_title', 10, 2 );

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Share Improve this question asked Feb 11, 2019 at 6:09 HenryHenry 98311 gold badge88 silver badges3131 bronze badges

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1 Answer 1

Sorted by: Reset to default 0

Here it is:

if ( get_post_type $id ) == 'tools-in-2019' {

Basically what your doing in this line makes no sense at all - you try to compare if conditions with some string... And you try to call a function, but you’re ignoring all PHP syntax.

It should be like this:

if ( get_post_type( $id ) == 'tools-in-2019' ) {