/ 设置 10 秒超时 // 每日统计清 0 runtime_set('todaycomments', 0); runtime_set('todayarticles', 0); runtime_set('todayusers', 0); if ($forumlist) { $fidarr = array(); foreach ($forumlist as $fid => $forum) { $fidarr[] = $forum['fid']; } forum_update($fidarr, array('todayposts' => 0, 'todaythreads' => 0)); } // 清理临时附件 attach_gc(); // 当天24点 $today = strtotime(date('Ymd')) + 86400; runtime_set('cron_2_last_date', $today, TRUE); // 往前推8个小时，尽量保证在前一天 升级过来和采集的数据会很卡 // table_day_cron($time - 8 * 3600); cache_delete('cron_lock_2'); } } } ?>.push() value to JavaScript array (n) times using .fill()? - Stack Overflow|Concepts Of Algorithm
  2. Algorithm
  3. .push() value to JavaScript array (n) times using .fill()? - Stack Overflow

.push() value to JavaScript array (n) times using .fill()? - Stack Overflow

admin2025-04-19  2

Is it possible to .push() a value to an array but replicate the pushed value n times without using a traditional loop to perform the replication? For instance using .fill(). The examples I have seen declare a new Array() with a length of n, and .fill() it with a value. However, I have not seen any examples dealing with .push(), so I'm not even sure it is possible.

Example of what I'm looking for:

var my_array = [];
for (var i = 0; i < 5; i++) {
    my_array.push(5);
};

Scenario:

I'm pulling values from three different arrays or objects to populate a single matrix that will be ran through a Munkres (Hungarian) algorithm, in order to avoid introducing another loop I would like to .push values to the matrix and use .fill() to repeat the value n times.

Example:

var s = […];
var a = […];
var p = […];

var matrix = [];
for (var i = 0; i < s.length; i++) {
    var preferences = [];
    for (var j = 0; j < p.length; j++ {
        var pid = p[j];
        for (var k = 0; k < a.length; k++ {
            if (pid == a[k]) {
                for (var l = 0; l < 5; l++) {  // <-- THIS.
                    preferences.push(a[k]);
                };
            };
        };
    };
    matrix.push(preferences);
};

Is it possible to .push() a value to an array but replicate the pushed value n times without using a traditional loop to perform the replication? For instance using .fill(). The examples I have seen declare a new Array() with a length of n, and .fill() it with a value. However, I have not seen any examples dealing with .push(), so I'm not even sure it is possible.

Example of what I'm looking for:

var my_array = [];
for (var i = 0; i < 5; i++) {
    my_array.push(5);
};

Scenario:

I'm pulling values from three different arrays or objects to populate a single matrix that will be ran through a Munkres (Hungarian) algorithm, in order to avoid introducing another loop I would like to .push values to the matrix and use .fill() to repeat the value n times.

Example:

var s = […];
var a = […];
var p = […];

var matrix = [];
for (var i = 0; i < s.length; i++) {
    var preferences = [];
    for (var j = 0; j < p.length; j++ {
        var pid = p[j];
        for (var k = 0; k < a.length; k++ {
            if (pid == a[k]) {
                for (var l = 0; l < 5; l++) {  // <-- THIS.
                    preferences.push(a[k]);
                };
            };
        };
    };
    matrix.push(preferences);
};
  • javascript
  • arrays
Share edited Mar 25, 2019 at 23:08 artomason asked Mar 25, 2019 at 23:04 artomasonartomason 4,0336 gold badges28 silver badges45 bronze badges 2
  • I think you need to use fill, but without push - push returns the new length of the array. – Jack Bashford Commented Mar 25, 2019 at 23:08
  • The problem is I need to append the values to the preferences array so they are retained each iteration. I think if I create an array with the desired values and .push() that to the preferences array it would result in [[ ],[ ],[ ]] – artomason Commented Mar 25, 2019 at 23:09
Add a ment  | 

1 Answer 1

Reset to default 8

You could use concat and fill:

preferences = preferences.concat(Array(5).fill(a[k]));
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push() value to JavaScript array (n) times using fill()Stack Overflow

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