javascript - delete div on button click - Stack Overflow

admin2025-04-03 0

I am trying to delete the div on button click but the problem that I need the button to delete the div that it contain to without passing the id of the div to the delete button

so this code at the end should be able to delete the div without passing the id of the div instead it will depend on passing this reference

<!doctype html>
<html>

<head>
    <script src=".11.3/jquery.min.js"></script>
    <script>
        $(document).ready(function() {
            $(document).on('mouseenter', '#divbutton', function() {
                $(this).find(":button").show();
            }).on('mouseleave', '#divbutton', function() {
                $(this).find(":button").hide();
            });
        });
    </script>

    <style>
        #divbutton {
            height: 100px;
            background: #0000ff;
        }

        #divbutton2 {
            height: 100px;
            background: #0000ff;
        }

        #divbutton3 {
            height: 100px;
            background: #0000ff;
        }
    </style>
</head>
<body>
    <div id="divbutton">
        <button type="button" style="display: none;" id="i" onclick="document.body.removeChild(document.getElementById('divbutton'))">Hello</button>
    </div>

    <div id="divbutton2">
        <button type="button" style="display: none;" id="i" onclick="document.body.removeChild(document.getElementById('divbutton2'))">Hello </button>
    </div>

    <div id="divbutton3">
        <button type="button" style="display: none;" id="i" onclick="document.body.removeChild(document.getElementById('divbutton3'))">Hello </button>
    </div>
</body>

</html>

I am trying to delete the div on button click but the problem that I need the button to delete the div that it contain to without passing the id of the div to the delete button

so this code at the end should be able to delete the div without passing the id of the div instead it will depend on passing this reference

<!doctype html>
<html>

<head>
    <script src="http://ajax.googleapis./ajax/libs/jquery/1.11.3/jquery.min.js"></script>
    <script>
        $(document).ready(function() {
            $(document).on('mouseenter', '#divbutton', function() {
                $(this).find(":button").show();
            }).on('mouseleave', '#divbutton', function() {
                $(this).find(":button").hide();
            });
        });
    </script>

    <style>
        #divbutton {
            height: 100px;
            background: #0000ff;
        }

        #divbutton2 {
            height: 100px;
            background: #0000ff;
        }

        #divbutton3 {
            height: 100px;
            background: #0000ff;
        }
    </style>
</head>
<body>
    <div id="divbutton">
        <button type="button" style="display: none;" id="i" onclick="document.body.removeChild(document.getElementById('divbutton'))">Hello</button>
    </div>

    <div id="divbutton2">
        <button type="button" style="display: none;" id="i" onclick="document.body.removeChild(document.getElementById('divbutton2'))">Hello </button>
    </div>

    <div id="divbutton3">
        <button type="button" style="display: none;" id="i" onclick="document.body.removeChild(document.getElementById('divbutton3'))">Hello </button>
    </div>
</body>

</html>

Share Improve this question edited Jun 28, 2015 at 20:12 dfsq 193k26 gold badges242 silver badges259 bronze badges asked Jun 28, 2015 at 19:57 Bisher Andoura 1092 gold badges4 silver badges10 bronze badges

Format your javascript properly please. – user4938328 Commented Jun 28, 2015 at 20:02

Add a ment |

3 Answers 3

Sorted by: Reset to default 5

If you want to know how to use this reference to get hold of the parent element to pass it to removeChild, then it's quite easy, just use parentNode:

<div class="divbutton">
    <button type="button" style="display: none;" id="i" onclick="document.body.removeChild(this.parentNode)">Hello</button>
</div>

However, since you are using jQuery it makes sense to make use of it's power:

$(document).on('mouseenter', '.divbutton', function () {
    $(this).find(":button").show();
}).on('mouseleave', '.divbutton', function () {
    $(this).find(":button").hide();
}).on('click', ':button', function() {
    $(this).parent().remove();
});

I also changed ids #divbuttonX to class name .divbutton, CSS bees simpler in this case too.

Demo: http://jsfiddle/5qfjo0c7/

You can use .closest to remove the div

 $(document).ready(function () {
            $(document).on('mouseenter', 'div[id^=divbutton]', function () {
                $(this).find(":button").show();
            }).on('mouseleave', 'div[id^=divbutton]', function () {
                $(this).find(":button").hide();
            });
           $(document).on('click', 'button#i', function () {
                $(this).closest("div").remove();
            });

 });

#divbutton {
height: 100px;
background: #0000ff;
}

#divbutton2 {
height: 100px;
background: #0000ff;
}

#divbutton3 {
height: 100px;
 background: #0000ff;
}

<script src="https://ajax.googleapis./ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="divbutton">
<button type="button" style="display: none;" id="i"  >Hello</button>
</div>

<div id="divbutton2" >
<button type="button" style="display: none;" id="i">Hello    </button>
</div>

<div id="divbutton3" >
<button type="button" style="display: none;" id="i">Hello    </button>
</div>

Try this it would help:

$(this).parent().closest('div').hide();

$("button").click(function () {
    $(this).parent().closest('div').hide();
});

DEMO :

$("button").click(function () {
    $(this).parent().closest('div').hide();
});

#divbutton {
    background:powderblue;
    padding:10px;
    height:100px;
}

<script src="https://ajax.googleapis./ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<div id="divbutton">
<button id="i">Hello</button>
</div>

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