javascript - NodeJS, Firestore get field - Stack Overflow

I have firestore set up on my nodejs chatbot. And its successfully copying the Facebook users ID to .doc Name, and setting there username and other info under there user ID in firestore

How do i go about retrieving this "field" name to display back to user.

what i have so far is this

 const givename = db.collection('users').doc(''+ sender_id).get("name");  
 
 

I have firestore set up on my nodejs chatbot. And its successfully copying the Facebook users ID to .doc Name, and setting there username and other info under there user ID in firestore

How do i go about retrieving this "field" name to display back to user.

what i have so far is this

 const givename = db.collection('users').doc(''+ sender_id).get("name");  
 
 

How ever firebase is returning nothing.

Iv looked alot online on how to return a field. but with little luck. Any suggestions?

• javascript
• node.js
• firebase
• google-cloud-firestore

Share Improve this question Follow edited Oct 7, 2018 at 1:47 Mic asked Oct 7, 2018 at 1:41 MicMic 33311 gold badge22 silver badges1414 bronze badges

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3 Answers 3

Sorted by: Reset to default 15

Calling get() doesn't return the data immediately, since the data is loaded asynchronously. It instead returns a promise, which resolves once the data is loaded. This means that you can use await (as in Francisco's answer) or (if await is not available) implement the then() method:

db.collection('users').doc(''+ sender_id).get().then(function(doc) {
  console.log(doc.data().name);
});

A common pitfall to be aware of: the doc.data() is only available inside the callback,

Haven't worked with Firestore yet, but from reading https://firebase.google.com/docs/firestore/query-data/get-data

something like below should work (untested):

const userRef = db.collection("users").doc("1234")
const userDoc = await userRef.get()
const {name} = userDoc.data()
console.log(name)

Another way is:

const givename = await db.collection("users").doc("YOUR DOCUMENT NAME").get();

console.log(givename.data().name);

Remember to put this code in an async function since we are using await here