python ,use function timestamp() ,cause error Invalid argument - Stack Overflow

I want to extract two keywords of interest from a log file and calculate the time difference between them. Each line in the log starts with a timestamp in the following format. For example, I want to calculate the duration between the keywords abc and def.

01-20 09:18:42.637   721  4768 I abc : START a 
01-20 09:18:43.968   721   777 I hhhhh : fffffff
01-20 09:19:02.886 11719 11864 D def :end cccc

duration_List.append(float("%.3f" % (start_time.timestamp() - start_time.timestamp()))) ^^^^^^^^^^^^^^^^^^^^^^ OSError: [Errno 22] Invalid argumen

my code is

def Get_Line_Time_s(line):
    time_format = "%m-%d %H:%M:%S.%f"
    dt = datetime.strptime(line[:18], time_format)
    return dt  

def Calculate_Time(logcat_file, keyword_start, keyword_end):
    cmd = "grep -aEi '%s|%s' %s" % (keyword_start, keyword_end, logcat_file)
    print("\n Using command: %s" % cmd)
    tmp_file = TEMP_FILE
    if os.path.exists(tmp_file):
        os.remove(tmp_file)    

    with open(tmp_file, "w") as tmp:
        subprocess.run(["bash", "-c", cmd], stdout=tmp)
    tmp.close()
    logs = open(tmp_file, "r")
    read_lines = logs.readlines()

    duration_List = []
    pre_line = None
    for line in read_lines:
        if line.find(keyword_end) != -1 and pre_line != None:
            end_time = Get_Line_Time_s(line)
            print(end_time)
            start_time = Get_Line_Time_s(pre_line)
            duration_List.append(float("%.3f" % (end_time.timestamp() - start_time.timestamp())))
        pre_line = line

    logs.close()
    return duration_List

I am a new Python programmer, and I encountered this error but don’t know how to troubleshoot it. Could you please provide some guidance and help? Thank you very much!

It fixed by change code as follows @Vũ Trí Anh Hoàng

def Get_Line_Time_s(line):
    time_format = "%m-%d %H:%M:%S.%f"
    dt = datetime.strptime(line[:18], time_format)
    current_year = datetime.now().year
    dt = dt.replace(year=2025)
    return dt  

I want to extract two keywords of interest from a log file and calculate the time difference between them. Each line in the log starts with a timestamp in the following format. For example, I want to calculate the duration between the keywords abc and def.

01-20 09:18:42.637   721  4768 I abc : START a 
01-20 09:18:43.968   721   777 I hhhhh : fffffff
01-20 09:19:02.886 11719 11864 D def :end cccc

duration_List.append(float("%.3f" % (start_time.timestamp() - start_time.timestamp()))) ^^^^^^^^^^^^^^^^^^^^^^ OSError: [Errno 22] Invalid argumen

my code is

def Get_Line_Time_s(line):
    time_format = "%m-%d %H:%M:%S.%f"
    dt = datetime.strptime(line[:18], time_format)
    return dt  

def Calculate_Time(logcat_file, keyword_start, keyword_end):
    cmd = "grep -aEi '%s|%s' %s" % (keyword_start, keyword_end, logcat_file)
    print("\n Using command: %s" % cmd)
    tmp_file = TEMP_FILE
    if os.path.exists(tmp_file):
        os.remove(tmp_file)    

    with open(tmp_file, "w") as tmp:
        subprocess.run(["bash", "-c", cmd], stdout=tmp)
    tmp.close()
    logs = open(tmp_file, "r")
    read_lines = logs.readlines()

    duration_List = []
    pre_line = None
    for line in read_lines:
        if line.find(keyword_end) != -1 and pre_line != None:
            end_time = Get_Line_Time_s(line)
            print(end_time)
            start_time = Get_Line_Time_s(pre_line)
            duration_List.append(float("%.3f" % (end_time.timestamp() - start_time.timestamp())))
        pre_line = line

    logs.close()
    return duration_List

I am a new Python programmer, and I encountered this error but don’t know how to troubleshoot it. Could you please provide some guidance and help? Thank you very much!

It fixed by change code as follows @Vũ Trí Anh Hoàng

def Get_Line_Time_s(line):
    time_format = "%m-%d %H:%M:%S.%f"
    dt = datetime.strptime(line[:18], time_format)
    current_year = datetime.now().year
    dt = dt.replace(year=2025)
    return dt  

• python

Share Improve this question Follow edited Jan 21 at 8:51 morty morty asked Jan 21 at 8:06 morty mortymorty morty 1966 bronze badges 13

• Your indents is confusing. Please take the time to format your code as it is on your system and include the full traceback error. If the code is as-is your code, then you have an indentation issue. – ewokx Commented Jan 21 at 8:11
• Can you share what start_time and end_time are? – Mureinik Commented Jan 21 at 8:13
• 1 You can't possibly get an OSError from a float cast. – AKX Commented Jan 21 at 8:13
• 1 @ewokx I have updte the full code – morty morty Commented Jan 21 at 8:28
• 1 @globglogabgalab I passed string 01-20 09:19:02.886 11719 11864 D hh kkk and add print(end_time) to print it . the output is 1900-01-20 09:19:02.886000 I don't know why it print 1900 ? – morty morty Commented Jan 21 at 8:28

 |  Show 8 more comments

1 Answer 1

Sorted by: Reset to default 1

Because you don't have year in your datetime object

from datetime import datetime

time_str = "01-21 15:30:45.123456"
time_format = "%m-%d %H:%M:%S.%f"

dt = datetime.strptime(time_str, time_format)
new_dt = dt.replace(year=2025)

print(new_dt.timestamp()) # 1737448245.123456
print(dt.timestamp()) # Error Invalid argument